August 19, 1995
Source of results: Iowa Republican Party
| Place | Candidate | Votes | Percentage |
|---|---|---|---|
| 1 (tie) | Bob Dole | 2,582 | 24.4% |
| 1 (tie) | Phil Gramm | 2,582 | 24.4% |
| 3 | Pat Buchanan | 1,922 | 18.1% |
| 4 | Lamar Alexander | 1,156 | 10.9% |
| 5 | Alan Keyes | 804 | 7.6% |
| 6 | Morry Taylor | 803 | 7.6% |
| 7 | Richard Lugar | 466 | 4.4% |
| 8 | Pete Wilson | 129 | 1.2% |
| 9 | Bob Dornan | 87 | 0.8% |
| 10 | Arlen Specter | 67 | 0.6% |
| Total | 10,958 | 100% |
10,958 voters participated in the 1995 Ames Straw Poll. Bob Dole and Phil Gramm won with a tie. Bob Dole would go on to win the Republican nomination.
Read more about this topic: Ames Straw Poll, Results, Detailed Year-by-year Results
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