Lee-Kesler Method - Example Calculation

Example Calculation

For benzene with

  • Tc = 562.12 K
  • Pc = 4898 kPa
  • Tb = 353.15 K
  • ω = 0.2120

the following calculation for T=Tb results:

  • Tr = 353.15 / 562.12 = 0.628247
  • f(0) = -3.167428
  • f(1) = -3.429560
  • Pr = exp( f(0) + ω f(1) ) = 0.020354
  • P = Pr * Pc = 99.69 kPa

The correct result would be P = 101.325 kPa, the normal (atmospheric) pressure. The deviation is -1.63 kPa or -1.61 %.

It is important to use the same absolute units for T and Tc as well as for P and Pc. The unit system used (K or R for T) is irrelevant because of the usage of the reduced values Tr and Pr.

Read more about this topic:  Lee-Kesler Method

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